A ball is thrown vertically upward with initial speed 10 m/s. What is the maximum height (neglect air resistance)?

A ball is thrown vertically upward with initial speed 10 m/s. What is the maximum height (neglect air resistance)?

• A. Approximately 10 meters
• B. Approximately 2.5 meters
• C. Approximately 5.1 meters
• D. Approximately 7.0 meters

Answer: (C)

The maximum height is found when the ball’s velocity drops to zero at the top. With constant downward acceleration g, use v^2 = v0^2 - 2gh. Setting v = 0 and solving gives h = v0^2/(2g). Plugging in v0 = 10 m/s and g ≈ 9.8 m/s^2 yields h ≈ 100 / 19.6 ≈ 5.1 meters. So the ball rises to about 5.1 meters.

The maximum height is found when the ball’s velocity drops to zero at the top. With constant downward acceleration g, use v^2 = v0^2 - 2gh. Setting v = 0 and solving gives h = v0^2/(2g). Plugging in v0 = 10 m/s and g ≈ 9.8 m/s^2 yields h ≈ 100 / 19.6 ≈ 5.1 meters. So the ball rises to about 5.1 meters.